Question

In an parallelogram if one angle is 70°.Find all the other angles.​

Answer 1

Answer:

A is 70°

then, angle D will also 70°(vertically opposite angle)

draw a bisector from A to D

make a triangle ABD and ACD

in triangle ABD

let angle B be X then,

A+B+C=180°

35°+X+35°=180°

70°+X=180°

X=180°-70°

X=110°

B=110°

so if angle B is 110°

hence angle C is also 110°(vertically opposite angle)

Answer 2

$\huge\sf\pink{Answer}$

☞ ∠B and ∠D = 110°

☞ ∠A and ∠C = 70°

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ One angle of a Parallelogram is 70°

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

☆ All the other angles?

$\rule{110}1$

$\huge\sf\purple{Steps}$

So now ,

➝ $\sf \angle A = \angle C \qquad \bigg\lgroup Opposite\; Angles\bigg\rgroup$

➝ $\sf\color{aqua}{C = 70\degree}$

➳ $\sf\angle A + \angle B = 180\degree \qquad \bigg \lgroup Corresponding \ Angles\bigg\rgroup$

➳ $\sf 70\degree + \angle B = 180\degree$

➳ $\sf \color{lime}{ \angle B = 110\degree}$

➢ $\sf \angle B = \angle D \qquad\bigg\lgroup Opposite\: Angles \bigg\rgroup$

➢ $\sf\color{red}{\angle D = 110\degree }$

$\rule{170}3$