Question

in an R,L,C and an AC voltage source are all connected in series. When L is removed from the circuit, the phase difference between the voltage and current in the circuit is $\pi$/3 . If instead , C is removed , the phase difference is again $\pi$/3. The power factor of the circuit is

Answer 1

Answer:

In an R,L,C and an AC voltage source are all connected in series. When L is removed from the circuit, the phase difference between the voltage and current in the circuit is /3 . If instead , C is removed , the phase difference is again /3.

The power factor of the circuit is

cos¢=R/z = z/z= 1

Answer is 1

Explanation:

PLEASE MARK MY ANSWER AS A BRAINLIEST ANSWER... I AM IN NEED OF THAT

FOLLOW ME

Answer 2

Answer:1

Explanation:

As here both cspacitative and inductive reactance are same and R is constant so phase difference remain same asXl=Xc then Z=R then value of cos is 1 so power factor is 1 here and we know if it is only possiblewhen both Xl=Xc oherwisr phase difference will never be same