in an right angled triangle ABC, angle ACB = 60 degrees, angle BAC = 30 degrees and angle ABC =90, then the length of BC is what cm?
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We can say that the radius(r) of the circumcircle will be BC/2
and, sin (∠ACB) = AB/BC
⇒ √3/2 = AB/2r
⇒ r/AB = 1/√3
∴ The ratio of the circum radius of the triangle to the side AB is 1 : √3
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