Physics, asked by 12subhrasouravswain3, 1 day ago

In an RL Series chrecuit R = 10Omega ,inductive reactance =8.66. If the current in the circuit is (5-i10)A Then Find Out active power​

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Answered by s12909csarishti23843
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ans 2

Explanation:

In an RL Series chrecuit R = 10Omega ,inductive reactance =8.66. If the current in the circuit is (5-i10)A Then Find Out active power

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