Question

In an S.H.M., displacement of the particle is 10.2 m and acceleration is 2 m/s² at any time, then the angular frequency is equal to

(A) 10 rad/s
(B) 0.1 rad/s
(C) 1 rad/s
(D) 100 rad/s​

Answer 1

Answer:

100 rad/s is the answer bro

Answer 2

Answer:

Given = displacement = 0.2 m

            accelaration = 2 m/s²

To find = angular frequency

solution=

Time period in S.H.M. = T = 2π/ω√x/a

x= displacement

a = accelaration

ω = √a/x

ω=  √2.0 /0.02

ω² =  2.0 / 0.02

ω²= 1-00

ω= 10 rad /s

so optionA is correct answer