In an triangle ABC right angled at A. If tan c=root 3. Find Sin B cos c plus cos b sin c.
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Answered by
2
Answer:
sin A=sin 90° =1
Step-by-step explanation:
tan C =√3= tan 60°
So C=60°
Now SinBcosC+ cosB sinC
=sin( B+C)
=sin( A+B+C-A)
=sin(180°-A) ( Because in a triangle A+B+C=
=sin A
=sin 90° =1
Answered by
0
Answer:
Sin 90° = 1
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