In an triangle C=105° ,B=45° ,a=2 find b.
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Step-by-step explanation:
So, let’s get started-
In the question, angle c= 105°,
Then, angle B= 45
So, angle a=45° (obviously)
And, AC= 2unit (as you have not provided any specific unit)
So, applying the so called, “Sine Theorem” over here-
sin B/AC = sin C/AB
So, sin 30°/82= sin 45°/AB
Let’s get this quick-
Putting the value of sin 30° and sin 45°,
AB= 2*{(2)^(1/2)} unit
So, AB= 2*1.414 unit
Thus, we arrived at our final result-
AB= 2.828unit (approximately)
or b=2.828unit it's may be
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