Math, asked by Asker1981, 6 hours ago

In an triangle PQR P=(2x+10) degree Q=(x+70) degrees and R=(2x+20) degrees find the value of X . Answer is P = 42° R=52° Q=86° Tell method Please

Answers

Answered by kumarimrinalini83

1

Answer:

the sum of all angles in a triangle is 180degrees then

agle P+ angle Q + angle R= 180 degrees

2x+10 + x+70 +2x+20= 180

5x+100= 180

5x= 80

x= 16

P= 2×16+10= 42

Q= 16+70= 86

R= 2×16+20= 52

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