Question

in and arithmetic progression first term - 3 second term is 4 then what is 21st term​

Answer 1

Answer:

the 21st term is 137

Step-by-step explanation:

given,

first two terms of an AP are a= -3 and a+d =4

=> - 3 + d =4

common difference,d= 7

a-(21)=a +(21 - 1) [a-(n)=a+(n-1)d]

=-3 +(20)7

=-3+140= 137