in angle ABC ,ad is the perpendicular bisector of BC show that angle abc is an isosceles triangle in which ab is equal to ac
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Since, AD is a perpendicular bisector of BC
We get BD = DC and ∠ADB = ADC = 90°
Now,
In triangle ADB and ADC,
AD = AD (common)
∠ADB = ADC = 90° (given)
BD = DC (given)
(SAS congruency)
Thus, AB = AC (corresponding parts of congruent triangles)
Hence, triangle ABC is an isosceles triangle.
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