Question

in angle ABC and xyz,BC =YZ and median AD=median XE. prov9e that : ABD parallel to angle Xye​

Answer 1

Answer:

==>∆XYZ ~∆DEF is correct answer

Step-by-step explanation:

$given$

In ∆XYZ ~ ∆DEF

XY/DE = YZ/EF = XA/DB ----------> (1)

$To prove$ ∆XYZ ~∆DEF

$proof$ since XA and DB are medians

YA= YZ

EB = EF ------------>2

$from (1)&(2)$

XY/DE = YA/DE = XA/DB

===>∆XYA ~ ∆ DEB $(by SSS)$

===> Y = E --------->3

Now in ∆XYZ and∆DEF

XY/DE = YZ/ EF

===>∆XYZ ~ ∆DEF (by SSS)

===>Hence, it's is proved.