in angle abc angle ais 70 and ad is perpendicular to bc. if angle c 50 find angle dac and abc
rranjana44:
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Given
Angle A=70°
AD Perpendicular BC.
So Angle ADC and ADB=90°
Also,AngleC=50°
In ∆ADC.
By angle sum Prpty of a Triangle...
180°=dac+adc+acd
→180°=50°+90°+dac
→Angle dac=180°-140°=40°.
Given,AngleA=70°
But angle A=dac+dab
→70°=40°+dab
→angle DAB=70-40=30°
in ∆DAB.
By angle Sum Prptg of a Triangle.
180°=dab+adb+abd
→Angle ABD=180°-(30°+90°)=180°-120°=60°
→Angle ABC=60° (angle abc is same as angle abd)
So angle DAC=40°
And angle ABC=60°
Hope It helps...
Regards,
Leukonov.
Angle A=70°
AD Perpendicular BC.
So Angle ADC and ADB=90°
Also,AngleC=50°
In ∆ADC.
By angle sum Prpty of a Triangle...
180°=dac+adc+acd
→180°=50°+90°+dac
→Angle dac=180°-140°=40°.
Given,AngleA=70°
But angle A=dac+dab
→70°=40°+dab
→angle DAB=70-40=30°
in ∆DAB.
By angle Sum Prptg of a Triangle.
180°=dab+adb+abd
→Angle ABD=180°-(30°+90°)=180°-120°=60°
→Angle ABC=60° (angle abc is same as angle abd)
So angle DAC=40°
And angle ABC=60°
Hope It helps...
Regards,
Leukonov.
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