in angle abc angle b 90 if sin a 9/41 find cos a
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Answered by
0
Correct option is
A
1
cosA=
41
9
cosA=
H
B
=
41
9
Using Pythagoras Theorem,
H
2
=P
2
+B
2
41
2
=P
2
+9
2
P=40
Now,
sin
2
A
1
−cot
2
A
= cosec
2
A−cot
2
A
= (
P
H
)
2
−(
P
B
)
2
= (
40
41
)
2
−(
40
9
)
2
=
1600
1600
= 1
Answered by
0
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