Question

In angle ABC , area B =,90°and tanA=1 . Then show that 2sin A cos A=1 .​

Answer 1

TO PROVE : 2SIN A COS A = 1

TAN A = 1

TAN A = TAN 45°

A = 45°

TAKING LHS IN THAT TO PROVE

2SIN A COS A = 2 1/ROOT 2 ×1/ROOT 2

=2×1/2 = 1 // HENCE PROVED

MARK THIS AS BRAINLIEST

Answer 2

Answer:

Step-by-step explanation:

if angle b=90 then tanA=1 then in triangle ABC hypotenuse will be root2

then sinA=1/root2 and cosA=1/root2

then 2(1/root2)(1/root2)

=2(1/2)

=1