Question

In angle ABC,c=90°,AB = 17 cm and AC = 15 cm.

Answer 1

Step-by-step explanation:

as angle c= 90°

therefore, AB is the hypothenuse Let BC = x

AB^2 = AC^2 + BC^2

=>

${17}^{2} = {15}^{2} + {x}^{2} \\ x = \sqrt{ {17}^{2} - {15}^{2} } \\ x = \sqrt{289 - 225} \\ x = \sqrt{64} \\ x = 8$

Therefore BC= 8cm