In angle ABC if ∆A=100 and AB=AC.find ∆B ∆C
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Answer:
Angle B = 40°
Angle C = 40°
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.GIVEN(AB=AC)
.Angle A + Angle B + Angle C = 180°
100°. +. Angle B + Angle C = 180°
100°. +. 2x. = 180°
2x. = 180° - 100° = 80°
x. =80/2
x. =40°
so Angle B = 40°
Angle C = 40°
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