Question

In angle ABC, if angle A=100°,AD bisects Angle A and AD | BC. Then, angle B
(a) 50°
(b)90°
(c)40°
(d)100°​

Answer 1

Answer:

40

Step-by-step explanation:

=In △ABC,∠BAD+∠ADB+∠DBA=180 (by angle sum property of a triangle.)

=50°+90°+∠DBA=180°

=∠DBA=180°−140°=40°