Question

In angle ABC, ZA = ZB = 62°; find ZC.

wrong answers reported ​

Answer 1

Answer:

<C = 56°

Step-by-step explanation:

In ∆ABC

<A + <B + <C = 180(BY ANGLE SUM PROPERTY OF ∆)

A/Q

62 + 62 + < C = 180

124 + <C = 180

<C = 180 - 124

<C = 56

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Answer 2

In any triangle, Sum of all the angles is 180⁰. This is called Angle Sum Property.

GIVEN: Trangle ABC, ∠A = ∠B = 62⁰

So, ∠A + ∠B + ∠C = 180⁰ [A.S.P]

---> 62⁰ + 62⁰ + ∠C = 180⁰

---> 124⁰ + ∠C = 180⁰

---> ∠C = 180⁰ - 124⁰

---> ∠C = 56⁰

∴ Value of ∠C is 56⁰