Question

in angle PQR an isosceles triangle with PQ=PR.if angle R=42,find the measure of angle P

Answer 1

Hi friend!

Since PQ = PR, Angle R = Angle Q = 42°
Sum of all angles = 180°
42° + 42° + P = 180°
P = 180° - 84° = 96°

Angle P = 96°

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Answer 2

HEYA DEAR ,

HERE IS YOUR ANSWER,

______________________________

IN ∆PQR

GIVEN. 1 PQ=PR
2. ∆R=42°


NOW,
IN THIS TRIANGLE

∆R=∆Q

【【(TWO EQUAL SIDES OF A TRIANGLE OPPOSITE TO THEIR ANGLES ARE ALSO EQUAL)】】

WE KNOW THAT THE SUM OF THE ANGLES OF A TRIANGLE IS 180°✔️

✴️✴️✴️✴️✴️✴️✴️
SO
∆P+∆Q+∆R=180
∆P+42+42=180
∆P=180-84
∆P=96°✔️


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