In angle PQR, if PR square + QR square, state with reason whether angle PQR is right angled triangle or not
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yes it is right angle triangle
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Step-by-step explanation:
This is converse of Pythagoras theorem
We can prove this contradiction sum q ²=p ²+r ²
in ΔPQR while triangle is not a rightangle
Now consider another triangle ΔABC we construct ΔABC AB=qCB=b and C is a Right angle
By the Pythagorean theorem (AC) ²
=p ²+r ²
But we know p ²+r ²=q ²
and q=PR
So (AB) ²=p ²+r ²=(SR) ²
Since PQ and AB are length of sides we can take positive square roots
AC=PQ
All the these sides ΔABC are congruent to ΔPQR
So they are congruent by sss theorem
Hope i am right
Here the explaination
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