Question

In Angle PQR , PQ = 8 cm and RT = 6 cm. Find the area of[ ¡] angle PQR [ ¡¡] the length of QS ​

Answer 1

Answer:

Let the base of the triangle be PQ=4 cm, then the height is RT=6 cm.

Hence area of triangle

=

2

1

base×height=

2

1

(4)(6)=12 cm

2

Now A=12 cm

2

Hence,

2

1

PR×QS=12⟹

2

1

×8×QS=12

⟹QS=3 cm