Question

In Angle PQR PR=10 and PQ=5. Find Angle Q and R by trigonometry equation?

Answer 1

Answer:

let PR be hypotaneous and PQ br Base

as we know cos Ф = base /hypo.

so cos Ф = 5/10 =1/2 = 60°

hence angle P is 60°

so obviously ∠Q = 90°

and now as we know two out of three angles of a triangle calculate the third angle simply  angle Rcan also be find out by sin Ф = perpendicul /base

=5/10 =1/2 =30°

hope it helpful dear friend!!!!

Step-by-step explanation: