Question

in angleabc witha a right angle at c,bc+ca=23cm bc-ca=7cm then find sina+cosA=?
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Answer 1

Answer:

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Answer 2

Answer

23/13

Step-by-step explanation:

draw the figure with the right angle at c and take the 2 equations

BC+CA=21 cm

BC-CA=7 cm

Add these 2 equations and we get,

2BC=30 so BC=15 cm

and now we Find CA BY substituiting the value of BC as 15 so we get 15+CA=23 and therefore CA=8 cm and now we can find third side by pythagoras theorem.

Now we get, 15 squared + 8 squared = x squared

225+64=x squared ; 289=x squared

so x= root of 289=17 cm

so AB or the hypotenuse is 17 cm.

Now we got the measures of all sides and now we find sin(A) and cos(A)

SOH CAH TOA(sorry i am still using these)

sin(angle a)=opposite/hypotenuse=15/13

cos(angle a)=adjacent/hypotenuse=8/13

so sin (a)+ cos(a)=15/13+8/13=23/13