In annual day of a school , age wise participation of students is shown in following frequency distribution..... Find the mean age of the participants.
Mean ?Age Number of Students5 – 7207 – 9189 – 112211 – 132513 – 152015 – 171517 – 1910
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5+7207++112211+9189+132513+152015+171517+1910
=155686/8=19460.65
=155686/8=19460.65
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