in annual function of a school student are standing in a rows there are 20 students in each row if the no of rows is K then find no. of students in the school ?
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Let the number of rows be x rows and the number of students in each row be y students .
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question ,
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xy
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And (x+3)(y−1)=xy
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And (x+3)(y−1)=xy⇒xy−x+3y−3=xy
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And (x+3)(y−1)=xy⇒xy−x+3y−3=xy−x+3y=3⟶(ii)
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And (x+3)(y−1)=xy⇒xy−x+3y−3=xy−x+3y=3⟶(ii)x−2y=2
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And (x+3)(y−1)=xy⇒xy−x+3y−3=xy−x+3y=3⟶(ii)x−2y=2−x+3y=3
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And (x+3)(y−1)=xy⇒xy−x+3y−3=xy−x+3y=3⟶(ii)x−2y=2−x+3y=3On adding , y=5 students.
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And (x+3)(y−1)=xy⇒xy−x+3y−3=xy−x+3y=3⟶(ii)x−2y=2−x+3y=3On adding , y=5 students.putting the value of y in equation ⟶(i)
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And (x+3)(y−1)=xy⇒xy−x+3y−3=xy−x+3y=3⟶(ii)x−2y=2−x+3y=3On adding , y=5 students.putting the value of y in equation ⟶(i)x−2(5)=2
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And (x+3)(y−1)=xy⇒xy−x+3y−3=xy−x+3y=3⟶(ii)x−2y=2−x+3y=3On adding , y=5 students.putting the value of y in equation ⟶(i)x−2(5)=2x=12 rows.
Let the number of rows be x rows and the number of students in each row be y students .Then the total number of students in a class =xy students.∴ According to the question , (x−2)(y+1)=xy⇒xy+x−2y−2=xyx−2y=2⟶(i)And (x+3)(y−1)=xy⇒xy−x+3y−3=xy−x+3y=3⟶(ii)x−2y=2−x+3y=3On adding , y=5 students.putting the value of y in equation ⟶(i)x−2(5)=2x=12 rows.∴ Total number of students in a classroom =(12×5)students =60 students.
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