in any boolean algebra show that if a≤b then a +bc = b(a+c)
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P1: a+b = b+a, a∙b=b∙a
(commutative)
P2: a+bc = (a+b)∙(a+c) (distributive)
a∙(b+c) = a∙b + a∙c
P3: a+0=a, a∙1 = a (identity)
P4: a+a’=1, a∙a’= 0 (complement)
2
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