Question

In any circle , chord AB and chord PQ are equidistant from centre of the circle. If AB = 6.4 cm then PQ =​

Answer 1

If two chords of a circle are equidistant from the center of the circle then they are 

A

Equal to each other

B

Not equal to each other

C

Intersect each other

D

None of these

Answer

Let AB,PQ be two chords, OC and OR be their distance from center.

Given

OC=OR

We know that BC=AC and PR=SR because perpendicular line from center bisects the chord.

In △OBC

BC2=r2–OC2–(1)

In △OPR

OP2=RP2+OR2

PR2=r2–OC2–(2)

(1)=(2)

⟹BC=PR⟹2BC=2PR

AB=PQ

Answer 2

Step-by-step explanation:

PQ is also 6.4 cm, because chords equidistant from it center are equal

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