Question

In any circuit it is containing a resistance of 102 and inductive reactance of 30 ohm in series
combination. Then analyzing phasor diagram find out the phasor angle of the circuit

Answer 1

Explanation:

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Answer 2

Given:

The resistance in the circuit = 102 Ω

The inductive reactance of the circuit = 30 Ω

To Find:

The phasor angle of the circuit

Solution:

The phasor angle of the circuit is Ф = sin⁻¹ (0.28).

In an RL circuit, the phasor angle is the base angle of a right-angled triangle in which the hypotenuse represents the impedance (Z), the base represents the resistance (R) and the perpendicular represents the inductive reactance (XL).

The impedance of an RL circuit = $\sqrt{R^2+X_L^2}$

Substituting the values,

Z = $\sqrt{102^2+30^2}$

= $\sqrt{10404+900}$

= $\sqrt{11304}$

= 106.32 Ω

The phasor angle can now be calculated using any of the trigonometric ratios.

sinФ = Perpendicular / Hypotenuse

= XL / Z

= 30 / 106.32

or Ф = sin⁻¹ (0.28)