In any exam 35% students failed in one subject 42 % student fail in other subject and 15% student fail in both subject if 2500 student present in exam then how many students have passed
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200student will pass
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Total is 100%
let x % be the passing students
35+42+15+x=100
x=100-92
= 8%
Passing students in no.= 8/100*2500
= 200 students
let x % be the passing students
35+42+15+x=100
x=100-92
= 8%
Passing students in no.= 8/100*2500
= 200 students
paper1 failed student = 35
paper2 failed student = 42
stud/
student failed on both = 15
assume no of candidate = 100
paper 1 passed student = 100-35=>65
paper 2 passed student = 100-42=58
students failed in paper1 only=35-15=20
students failed in paper2 only=42-15=27
candidate failed both paper=20+27+15=62
candidate Passed both paper=100-62=38
candidate Passed in paper1 only = 65-38=27
candidate Passed in paper2 only=58-38=20
either passed in paper1 & 2 = 27+20 =47
but actual student = 2500 in question
so 2500 *47/100 =1175
Similar questions
paper1 failed student = 35
paper2 failed student = 42
student failed on both = 15
assume no of candidate = 100
paper 1 passed = 100-35=>65
paper 2 passed = 100-42=58. failed in paper1 only=35-15=20
failed in paper2 only=42-15=27
candidate failed both paper=20+27+15=62
candidate Passed both paper=100-62=38
candidate Passed in paper1 only = 65-38=27
candidate Passed in paper2 only=58-38=20
either passed in paper1 & 2 = 27+20 =47
but actual student = 2500 in question
so 2500 *47/100 =1175.