Question

in any ionic crystal a has formed cubical close packing and B atoms are present at every tetrahedral voids. if any sample of crystal contain N number of B atoms then number of A atoms in that sample is ​

Answer 1

Answer:

Explanation:

Number of of atoms of A in CCP ,n= 1

Number of tetrahedral voids in CCP = 2n

n = total numbers of spheres in a crystal.

Number of voids= 2 × 1 = 2

Number of B atoms in single crystal = 2

if number N numbers of B atoms are present in the sample

Then numbers of A atoms present will be:

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