in any trangle ABCprove thata-b/c=sinA-B/2/cosc/2
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We know that for a triangle ABC
∠A+∠B+∠C=180
0
2
∠B+∠A
=90
0
−
2
∠C
sin(
2
A+B
)=sin(90
0
−
2
C
)
=cos(
2
C
)
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