Math, asked by marasimmaharjan77, 28 days ago

In any triangle ABC B is 120° a is 1 and c is 5 then other angles and sides are?​

Answers

Answered by nilaypratap4
16

Answer:

a+c=180

1+5=180

6=180

=30 degree

a+c=180

a+b=180-6

=174

Step-by-step explanation:

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Answered by amitnrw
1

Given :  in a triangle ABC, B=120°,a=1, c = 5

To find : other angles and sides​

Solution:

triangle ABC

a = 1 , b =?,  c = 5

∠B = 120° , ∠A = ∠C = ?

b² = a² + c² - 2acCosB

=> b² = 1² + 5² - 2(1)(5)Cos120°

=> b² = 1+ 25 - 10(-0.5)

=> b² = 26 + 5

=> b² = 31

=> b = √31

a/SinA  = b/SinB = c/SinC

=> 1/SinA = √31/Sin(120°) = 5/SinC

=> SinA = 0.1555 => A  = 8.95°

=> C = 180° - 120° - 8.95° = 51.05°

b = √31

A = 8.95° , C =  51.05°

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