In any triangle ABC, if angleA - angleB = 33° and angleB – angleC = 18°, then find the value of angle B.
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Answer:
In triangle ABC
a-b=33
a=33+b ------------1
b-c=18
c=b-18 ------------2
Now in triangle abc by angle sum property
a+b+c=180
33+b+b+b-18=180 (by 1 and 2)
15+3b=180
3b=180-15
3b=165
b=165/3
b=55
Now put value of b in eq. 1 and 2
a-b=33
a-55=33
a=33+55
a=88
b-c=18
55-c=18
c=55-18
c=37
Your answer is:
a=88
b=55
c=37
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