Math, asked by ofrosy, 3 months ago

in any triangle prove that (AB+BC)/AC=Cot B/2

Answers

Answered by TarunKumarSingh
1

Step-by-step explanation:

Hii, your answer is:

By sin rule

a /sin A = b /sin B = c/ sin C = 2 R

(AB+BC)/AC= c + a / b = sin a' + sin A / sin B

= 2 sin (A+C /2) cos ( A - C /2) / 2 sin (B/2) cos (B/2)

= {2 cos B/2 cos A- C /2 } / {2 sin (B/2) cos (B/2)}

= {cos A - C /2} / sin B/2

= cos B/2 / sin B/2

= cot B /2.

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