in any triangle xyz the bisector angle Y and angle Z meet at I from point O,op perpendicular Y Z ,oq perpendicular zx and or perpendicular xy respectively prove that PQ equal to oq equal to or
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Step 1:
To Prove: OP=OQ=OR
Proof:
In ΔYRO and
∠RXO=∠PYO [because YO is the bisector of ∠Y]
∠YRO=∠YPO [each equal to 90°]
YO = YO [common]
Step 2:
⇒OP = OR (cpct) ... (i)
Step 3:
Similarly,
In ΔZPO and ΔZQO,
⇒OP = OQ (cpct).... (ii)
And In
Step 4:
ΔXRO and ΔXQO,
⇒OQ = OR (cpct)..... (iii)
From (i), (ii) and (iii), we get
Step 5:
OP = OQ = OR
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