Math, asked by marakebrith80, 1 month ago

in ap 3,8,13,18...is 310 a term of the ap​

Answers

Answered by surajjaiswal27236
0

Answer:

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Step-by-step explanation:

Given sequence is 3,8,13,...

The first term a=3 and

the common difference d=8−3=5

Let the n

th

term be 302

We know that the n

th

term of the arithmetic progression is given by a+(n−1)d

Therefore, a+(n−1)d=302

⟹3+(n−1)∗(5)=302

⟹3−5+5n=302

⟹−2+5n=302

⟹5n=304

⟹n=

5

304

n cannot be a fraction. Therefore, 302 is not the term of the given A.P.

Answered by kaycee27
1

Answer:

Step-by-step explanation:

A.P= 3,8,13,18

a=3

d= 8-3= 5

let a^n be 310

then a^n= a+(n-1)d=310

3+(n-1)5=310

(n-1)5=310-3

(n-1)5= 307

n-1= 307/5

n-1= 61.4

n= 61.4+1

n=62.4

as n is a term and a term can never be in decimals, fraction or can never be negetive.

therefore, no 310 is not the term of the given ap

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