in AP 6th term is 1 more than twice the third term the sum of the fourth and fifth term is 5 times the second term find the 10th term of AP
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a6=2(a3)+1
a+5d =2(a+2d)+1
a+5d=2a+4d+1
a-2a+5d-4d-1=0
-a+d-1=0...............(1)
a4+a5=5(a2)
a+3d+a+4d=5(a+d)
2a+7d=5a+5d
5a-2a+5d-7d=0
3a-2d=0
3a=2d
a=2d/3.............(2)
Substituting this value in equation 1
-(2d/3)+d-1=0
-2d+3d-3=0
d-3=0
d=3.............(3)
Substituting this value in equation 2
a=2(3)/3
a=6/3
a=2
a10=a+9d
=2+9(3)
=2+27
=29
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