Question

In AP an=8n+12 then find a12

Answer 1

Answer:

putting n=1

we get an= 8+12=20

again putting n=2

we get 8×2 +12= 28

similarly n=3

an= 24+12= 36

hence in the AP a=20 and d=8

so a12 = a+(n-1)d

= 20+ 11× 8

= 20 + 88

= 108 (answer)

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Answer 2

Answer:

$a _{n} = 8n + 12 \\ then... \\ a _{12} = 8 \times 12 + 12 \\ a _{12} = 96 + 12 \\ a _{12} = 108$