in ap if 10th term of an ap is 18 and 18th term is 10 and find 28th term
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Step-by-step explanation:
We know that the n
th
term of the arithmetic progression is given by a+(n−1)d
Given that 10
th
term of an A.P. is 41
Therefore, a+(10−1)d=41
⟹a+9d=41 ---------(1)
Given that 18
th
term of an A.P. is 73
Therefore, a+(18−1)d=73
⟹a+17d=73 ---------(2)
subtracting eqn (2) from eqn (1) gives (a+17d)−(a+9d)=73−41
⟹8d=32
⟹d=4
substituting d=4 in eqn (1) we get
a+9(4)=41
⟹a=41−36=5
Therefore, 26
th
term is a+(26−1)d=5+25(4)=105
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