in ap multiplying by m with mth term and multiplying by n with nth term. let two terms are equal. find the (m+n)th term
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Answer:
to find:
a+(m+n-1)d
given:
m(a+(m-1)d)= n(a+(n-1)d
ma+ md(m-1)= na + nd(n-1)
ma-na +md(m-1) - nd(n-1)=0
a(m-n) + m^2d - md - n^2d +nd =0
a(m-n) + d(m^2-n^2 - m + n)=0
a(m-n) + d( (m+n) (m-n) - (m-n))=0 (using identity a^2-b^2=(a+b)(a-b))
a(m-n) + d ( (m-n)(m+n-1))=0
(m-n) (a+ (m+n-1)d)=0
a+(m+n-1)d = 0* (m-n)
HENCE,
a+(m+n-1)d=0
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