Question

in AP no between 10 to 200 divisible by 7​

Answer 1

Answer:

27

Step-by-step explanation:

AP: 14, 21,...,196

SO, a(n)=a+(n-1)d

196=14+(n-1)7

196=14+7n-7

196=7+7n

189=7n

n=189/7

n=27

Answer 2

Answer: number of terms between 10 and 200 that are divisible by 7 = 27

Step-by-step explanation:

The question is not very clear.... if you want to know the number of terms between 10 and 200 that are divisible by 7 the here is the procedure

The first number divisible is 14

Therefore the AP is as follows:

14, 21, 28,...... 196

Let the first number be a = 14

The last number be $a_{n} = 196$

The common difference be d = 7

To find the last term of the AP we use the formula

$a_{n} = a + (n-1)*d$

Where n = number of terms between the first and the last number

Using the formula and substituting the values,we get

196 = 14 + (n-1)*7

=> 182 = 7*(n-1)

=> 26 = n - 1

=> n = 27

Therefore the number of terms between 10 and 200 that are divisible by 7 are 27

Please brainlist my answer, if helpful!