Question

in AP sn = 3n square + n and then find first two terms of AP

Answer 1

Answer:

Given Sn=3n²+n

Sn=n/2[2a+(n-1)d]

3n²+n=n/2[2a+(n-1) d]

....

solve this and after this factorise the equation you get the answer.

Step-by-step explanation:

thank u...

Answer 2

Hey,

Your Answer:

Sn = 3n²+n

First term: n = 1

= 3(1)²+1 = 4

Seconf term: n = 2

= 3(2)²+2 = 14