Question

In Ap, Sn=4n^- 3n, then a10​

Answer 1

Answer:

S

n

=4n

2

−3n

Now, S

n+1

=4(n+1)

2

−3(n+1)

We know that, t

n+1

=S

s+1

−S

n

t

n+1

=4n

2

+5n+1−4n

2

+3n

t

n+1

=8n+1

Thus t

n+1

is linear equation of n

hence it is an A.P

Now t

n+1

=8n+1

comlplaning with a

n+1

=a+(n−1)

a=1 and d=8