In APQR and AABC, if PQ = AB, ZQ E ZB, QR = BC, then th
triangles are congruent according to the which rule.
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In ΔABC and ΔPQR
AB=PQ
And BC=QR
CB And RQ extended to X and Y
∠ABX=∠PQY
∠ABC=180
o
−∠ABX=180
o
∠PQY
∠PQR=180
o
−∠PQY=∠ABC
We get in both triangles
AB=PQ
BC=QR
And ∠ABC=∠PQR
Then both triangle are congruent
i.e. ΔABC=ΔPQR
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