In APQR, seg QT 1 side PR.
If PT = 4 and RQ = 9 PQ = 8
find cos0 and sin0.
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Step-by-step explanation:
In△PQS
Bypythagorastheorem,
PS
2
+SQ
2
=PQ
2
⟹PS
2
=PQ
2
−SQ
2
⟹PS
2
=10
2
−6
2
⟹PS
2
=100−36=64
⟹PS=8
In△PSR
⟹PS
2
+RS
2
=PR
2
(pythagoras)
⟹PR
2
=PS
2
+RS
2
⟹PR
2
=64+(RQ+QS)
2
=64+15
2
⟹PR
2
=64+225
⟹PR
2
=289
⟹PR=17cm
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