In APQR, ZQ = 90°. S and T are points on QR
and PR respectively such that ZRTS = 90°. If
PR = 25 cm, QR = 24 cm and ST =5 cm, find
ar(ARST
ar(quadrilateral PQST),
Answers
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1
Answer:
As per Pythagorean theorem
PT
2
=PQ
2
+QT
2
....(in triangle QPT)
⇒QT
2
=PT
2
−PQ
2
And PR
2
=PQ
2
+QR
2
( in the triangle APR and given T is the mide point QR then QR=2QT) put value
⇒PR
2
=PQ
2
+(2QT)
2
⇒PR
2
=PQ
2
+4QT
2
⇒PR
2
=PQ
2
+4(PT
2
−PQ
2
)
=PQ
2
+4PT
2
−4PQ
2
⇒PR
2
=4PT
2
−3PQ
2
.
Step-by-step explanation:
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