In aright angle triangle ABC right angle is at c bc + ca =23 and bc - ca = 7 then find the sin A and tan B
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Step-by-step explanation:
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Sin A = 15/17 and Tan B = 8/15
Step-by-step explanation:
bc + ca = 23 ---(1)
bc - ca = 7 ---(2)
adding equation (1) and (2)
bc + ca + bc - ca = 23 + 7
2bc = 30
therefore, bc = 15
putting bc= 15 in equation (1)
15 + ca = 23
ca = 23 - 15 = 8
BC = 15 and CA = 8
Applying Pythagoras theorem,
ab² = bc² + ca²
ab² = (15)² + (8)²
ab² = 225 + 64
ab = √289 = 17
then, sin A = P/H = bc/ab= 15/17
and tan B = P/B = ac/bc = 8/15
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