In Arithmatic sequence 7th
number egual to a fourth
times of second
number
find a sequence
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In Arithmatic sequence 7th number equal to a fourth times of second number,where first term is 2
find a sequence
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- in an arithmetic Sequence
- 7th term is equal to the fourth times second no
- if a = 2
- The sequence
Tn = a + (n-1)d
Here
- 7th term is
T7 = a+(n-1)d
=>T7 = a+6d
- 2nd term
=>T2=a+(n-1)d
=>T2=a+(1)d
=>T2=a+d
According to the question
- 7th term is equal to the fourth times second no
=>T7=4(T2)
=>a+6d=4(a+d)
=>a-4a-4d+6d=0
=>-3a+2d=0
=>2d=3a
=>d=3a/2
Putting value of a
=>d=3
Then sequence is
=>2,5,8,11,...
Answered by
0
Tn = a + (n-1)d
Here
7th term is
T7 = a+(n-1)d
=>T7 = a+6d
2nd term
=>T2=a+(n-1)d
=>T2=a+(1)d
=>T2=a+d
According to the question
7th term is equal to the fourth times second no
=>T7=4(T2)
=>a+6d=4(a+d)
=>a-4a-4d+6d=0
=>-3a+2d=0
=>2d=3a
=>d=3a/2
Putting value of a
=>d=3
Then sequence is
=>2,5,8,11,..
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