Question

In Arithmetic Progression first term is 3and an = 4an−1 + 3, n > 1
find the 4th term?

Answer 1

Given: First term is 3, an = 4(a(n−1)) + 3, n > 1

To find: 4th term.

Solution:

• Since, we have given the first term, and the equation, lets find the second term, third term and fourth term using the given equation.
• So,

              a2 = 4( a (2-1)) + 3

              a2 = 4( a (1)) + 3

              a2 = 4( 3 ) + 3

              a2 = 15

• Similarly, we can find the values of third and fourth term.

              a3 = 4( a (3-1)) + 3

              a3 = 4( a (2)) + 3

              a3 = 4( 15 ) + 3

              a3 =63

• Also

              a4 = 4( a (4-1)) + 3

              a4 = 4( a (3)) + 3

              a4 = 4( 63 ) + 3

              a4 = 255

Answer:

      So the fourth term is 255.