Question

In arithmetic progression sum of third and fifth terms is 10 and product of second and fourth terms is - 15 then tenth term of the
progression is:
31
30
29
28

Show full procedure pls and fast ​

Answer 1

Answer:

please mark me as brain list

Step-by-step explanation:

Correct option is

A41Given that: t 1 +t 3 +t

5 =39t 2 +t 4 +t 6 =51To find:t 10

=?Solution:

Let a be the first term and d be thecommondifference.t1+t 3+t 5

=39or, a+a+2d+a+4d=39or, 3a+6d=39or,a+2d=13

+tt +tt =51

or, a+d+a+3d+a+5d=51

or, 3a+9d=51

or, a+3d=17

Subtracting eqn.(i) from eqn.(ii) we get,d=4Putting value d=4 in eqn.(i) we get,a+2×4=13or, a=13−8or, a=5

Now, t 10 =a+9dt 10 =5+9×4t 10 =5+36t 10 =41